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Si6392903

: How do I find a common complementary color? I have 3 colors, I need to find a 4th that is complementary of these three: #d9bba3 #72737b #b0aca8 I have so far found #d7d6db but it is only

@Si6392903

Posted in: #AdobePhotoshop #Color

I have 3 colors, I need to find a 4th that is complementary of these three:
#d9bba3 #72737b #b0aca8


I have so far found #d7d6db but it is only my guess, not based on any tool, is there a way to find a common complementary color? Do they have one in common?

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@Debbie163

Color is a complex issue.

Here is an answer I wrote to confuse you more: Is there a standard for color wheels?

So you need to choose which method to use.

Be careful on which color model you use, for example, there are some color tools online that do not use a standard color wheel (as you can read in the other post)

Try to use one RGB+CMYK one or as I call it RCGMBY one.

But also remember that color has three dimensions, so it is a solid, not a flat wheel.

As you used the tag Photoshop, here are two methods (among several others).

Open the image I prepared for you and press Ctrl+U or go to Adjustments>Hue/Saturation

And move the H slider +180. This will give you the complementary on the same plane. (Spanish class! Tono = Hue)



Or simply inverse the image. Here I am using curves:



This will give you the complementary in 3D, in a solid.



If you are looking for a color scheme, you can drop the two gray images. They are simply gray, and focus only in the blue.

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@Sarah814

Kuler is a great tool online for color schemes, and you can easily find complements to any value.

Or in Photoshop you can try this:

Open your Color Picker and select #d9bba3 for example.

Go to the H value (27°), add 180° (for 207°)
- there is your complementary color, #a3c0d9

If the Hue value is above 180° then subtract 180° instead:

207° - 180 = 27° (you are working within 360°).

If your colors were less friendly than this example you could try this with all of them to get a better idea of the range you are looking in.

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